Treat result of LuaL_len as int regardless

Since other part of lua-intf already doing the cast, let's make the code more consistent.
yihuang · Mar 18, 2016 · d6f17a8 · d6f17a8
1 parent 78ada90
commit d6f17a8
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Showing 2 changed files with 3 additions and 3 deletions.
diff --git a/LuaIntf/LuaState.h b/LuaIntf/LuaState.h
@@ -130,8 +130,8 @@ namespace Lua
     {
         luaL_checktype(L, index, LUA_TTABLE);
         LIST list;
-        auto n = luaL_len(L, index);
-        for (auto i = 1; i <= n; i++) {
+        int n = int(luaL_len(L, index));
+        for (int i = 1; i <= n; i++) {
             lua_rawgeti(L, index, i);
             list.push_back(pop<typename LIST::value_type>(L));
         }

diff --git a/LuaIntf/src/LuaCompat.cpp b/LuaIntf/src/LuaCompat.cpp
@@ -270,7 +270,7 @@ LUA_INLINE int luaL_len(lua_State* L, int i)
     luaL_checkstack(L, 1, "not enough stack slots");
     lua_len(L, i);
     int is_num = 0;
-    int res = (int)lua_tointegerx(L, -1, &is_num);
+    int res = int(lua_tointegerx(L, -1, &is_num));
     lua_pop(L, 1);
     if (!is_num) {
         luaL_error(L, "object length is not a number");