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Day 41.1.txt
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Day 41.1.txt
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415. Add Strings
Given two non-negative integers, num1 and num2 represented as string, return the sum of num1 and num2 as a string.
You must solve the problem without using any built-in library for handling large integers (such as BigInteger). You must also not convert the inputs to integers directly.
Example 1:
Input: num1 = "11", num2 = "123"
Output: "134"
Example 2:
Input: num1 = "456", num2 = "77"
Output: "533"
Example 3:
Input: num1 = "0", num2 = "0"
Output: "0"
Constraints:
1 <= num1.length, num2.length <= 104
num1 and num2 consist of only digits.
num1 and num2 don't have any leading zeros except for the zero itself.
class Solution {
public String addStrings(String n1, String n2) {
int i,j,k=0,k1=0,m,y=0,z;
String p="",q,r;
char c,c1;
m=Math.min(n1.length(),n2.length());
z=Math.max(n1.length(),n2.length());
r=z==n1.length()?n1:n2;
m--;
z--;
for(i=n1.length()-1,j=n2.length()-1;m>=0;i--,j--,m--,z--)
{
c=n1.charAt(i);
c1=n2.charAt(j);
k=Integer.parseInt(String.valueOf(c));
k1=Integer.parseInt(String.valueOf(c1));
k=k+k1+y;
if(k>=10)
{
q=String.valueOf(k);
c=q.charAt(q.length()-1);
y=Integer.parseInt(q.substring(0,q.length()-1));
p=c+p;
}
else
{
p=k+p;
y=0;
}
}
if(i==j)
{
if(y>0)
p=y+p;
return p;
}
else
{
for(;z>=0;z--)
{
c=r.charAt(z);
k=Integer.parseInt(String.valueOf(c));
k=k+y;
if(k>=10)
{
q=String.valueOf(k);
c=q.charAt(q.length()-1);
y=Integer.parseInt(q.substring(0,q.length()-1));
p=c+p;
}
else
{
y=0;
p=k+p;
}
}
if(y>0)
p=y+p;
if(n1.length()==n2.length())
return p.substring(1);
else
return p;
}
}
}