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Check_for_balanced_parenthesis.cpp
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Check_for_balanced_parenthesis.cpp
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/*
Check for balanced parenthesis
==============================
Given an expression containing parenthesis, check if it is well-formed or balanced.
A balanced parenthesis means for every opening bracket there must be equivalent closing brackets.
Application: Stack data structure
Author: @gargvader
Edit by: @Mohim-Singla
*/
#include <iostream>
#include <stack>
#include <string>
using namespace std;
// function to check if brackets are balanced
bool areBracketsBalanced(string expr)
{
stack<char> s;
char x;
// Traversing the Expression
for (int i = 0; i < expr.length(); i++)
{
if (expr[i] == '(' || expr[i] == '[' || expr[i] == '{')
{
// Push the element in the stack
s.push(expr[i]);
continue;
}
// IF current current character is not opening
// bracket, then it must be closing. So stack
// cannot be empty at this point.
if (s.empty())
return false;
switch (expr[i])
{
case ')':
// Store the top element in a
x = s.top();
s.pop();
if (x == '{' || x == '[')
return false;
break;
case '}':
// Store the top element in b
x = s.top();
s.pop();
if (x == '(' || x == '[')
return false;
break;
case ']':
// Store the top element in c
x = s.top();
s.pop();
if (x == '(' || x == '{')
return false;
break;
}
}
// Check Empty Stack
return (s.empty());
}
// Driver code
int main()
{
string expr;
cout << "Enter a expression " << endl;
cin >> expr;
// Function call
if (areBracketsBalanced(expr))
cout << "Balanced Parenthesis";
else
cout << "Unbalanced Parenthesis";
return 0;
}
/*
-------------------------------
Test case 1:
Input:
((a+b)+(c-d+f))
Output:
Balanced Parenthesis
-------------------------------
Test case 2:
Input:
{(a+b)+(c-d+f)]}
Output:
Unbalanced Parenthesis
---------------------------------
Test case 3:
Input:
(a+b)*{c*[a+b*(c+d)}]
Output:
Unbalanced Parenthesis
--------------------------------
Time Complexity: O(n)
Space Complexity: O(n)
*/